source: issm/trunk/test/Par/RoundSheetEISMINT.par@ 9684

%Ok, start defining model parameters here
disp('      creating thickness');
md.thickness=10*ones(md.numberofnodes,1);
md.bed=zeros(md.numberofnodes,1);
md.surface=md.bed+md.thickness;

disp('      creating drag');
md.friction.coefficient=20*ones(md.numberofnodes,1); %q=1. %no drag is specified in the analytical solution
md.friction.p=ones(md.numberofelements,1);
md.friction.q=ones(md.numberofelements,1);

disp('      creating temperatures');
tmin=238.15; %K
st=1.67*10^-2/1000; %k/m;
radius=sqrt((md.x).^2+(md.y).^2);
md.initialization.temperature=(tmin+st*radius);
md.basalforcings.geothermalflux=4.2*10^-2*ones(md.numberofnodes,1);

disp('      creating flow law paramter');
md.materials.rheology_B=6.81*10^(7)*ones(md.numberofnodes,1); %to have the same B as the analytical solution 
md.materials.rheology_n=3*ones(md.numberofelements,1);

disp('      creating surface mass balance');
smb_max=0.5; %m/yr
sb=10^-2/1000; %m/yr/m
rel=450*1000; %m
md.surfaceforcings.mass_balance=min(smb_max,sb*(rel-radius));

disp('      creating velocities');
constant=0.3;
md.inversion.vx_obs=constant/2*md.x.*(md.thickness).^-1;
md.inversion.vy_obs=constant/2*md.y.*(md.thickness).^-1;
md.inversion.vel_obs=(sqrt((md.inversion.vx_obs).^2+(md.inversion.vy_obs).^2));
md.initialization.vx=zeros(md.numberofnodes,1);
md.initialization.vy=zeros(md.numberofnodes,1);
md.initialization.vz=zeros(md.numberofnodes,1);
md.initialization.pressure=zeros(md.numberofnodes,1);

%Deal with boundary conditions:
disp('      boundary conditions for diagnostic model: ');
md=SetMarineIceSheetBC(md,'../Exp/RoundFrontEISMINT.exp');

radius=sqrt((md.x).*md.x+(md.y).*md.y);
pos=find(radius==min(radius));
md.x(pos)=0; md.y(pos)=0; %the closest node to the center is changed to be exactly at the center

md.diagnostic.spcvx(pos)=0;
md.diagnostic.spcvy(pos)=0;
md.diagnostic.spcvz(pos)=0;

%parallel options
md.timestepping.final_time=50000;

%Constants
md.materials.rho_ice=910;
md.materials.thermalconductivity=2.1;
md.materials.latentheat=3.35*10^5;
md.materials.beta=8.66*10^-4/(md.materials.rho_ice*md.constants.g); %conversion from K/m to K/Pa
md.constants.yts=31556926;