source: issm/trunk/test/Par/RoundSheetEISMINT.par

%Ok, start defining model parameters here
disp('      creating thickness');
md.geometry.thickness=10.*ones(md.mesh.numberofvertices,1);
md.geometry.base=zeros(md.mesh.numberofvertices,1);
md.geometry.surface=md.geometry.base+md.geometry.thickness;

disp('      creating drag');
md.friction.coefficient=20.*ones(md.mesh.numberofvertices,1);
md.friction.p=ones(md.mesh.numberofelements,1);
md.friction.q=ones(md.mesh.numberofelements,1);

disp('      creating temperatures');
tmin=238.15; %K
st=1.67*10^-2/1000.; %k/m
radius=sqrt((md.mesh.x).^2+(md.mesh.y).^2);
md.initialization.temperature=(tmin+st*radius);
md.basalforcings.geothermalflux=4.2*10^-2*ones(md.mesh.numberofvertices,1);

disp('      creating flow law parameter');
md.materials.rheology_B=6.81*10^7*ones(md.mesh.numberofvertices,1); %to have the same B as the analytical solution 
md.materials.rheology_n=3.*ones(md.mesh.numberofelements,1);

disp('      creating surface mass balance');
smb_max=0.5; %m/yr
sb=10^-2/1000.; %m/yr/m
rel=450.*1000.; %m
md.smb.mass_balance=min(smb_max,sb*(rel-radius));

disp('      creating velocities');
constant=0.3;
md.inversion.vx_obs=constant/2.*md.mesh.x.*(md.geometry.thickness).^-1;
md.inversion.vy_obs=constant/2.*md.mesh.y.*(md.geometry.thickness).^-1;
md.inversion.vel_obs=(sqrt((md.inversion.vx_obs).^2+(md.inversion.vy_obs).^2));
md.initialization.vx=zeros(md.mesh.numberofvertices,1);
md.initialization.vy=zeros(md.mesh.numberofvertices,1);
md.initialization.vz=zeros(md.mesh.numberofvertices,1);
md.initialization.pressure=zeros(md.mesh.numberofvertices,1);

%Deal with boundary conditions:
disp('      boundary conditions for stressbalance model:');
md=SetMarineIceSheetBC(md,'../Exp/RoundFrontEISMINT.exp');

radius=sqrt((md.mesh.x).^2+(md.mesh.y).^2);
pos=find(radius==min(radius));
md.mesh.x(pos)=0.; md.mesh.y(pos)=0.; %the closest node to the center is changed to be exactly at the center

md.stressbalance.spcvx(pos)=0.;
md.stressbalance.spcvy(pos)=0.;
md.stressbalance.spcvz(pos)=0.;

%parallel options
md.timestepping.final_time=50000.;

%Constants
md.materials.rho_ice=910.;
md.materials.thermalconductivity=2.1;
md.materials.latentheat=3.35*10^5;
md.materials.beta=8.66*10^-4/(md.materials.rho_ice*md.constants.g); %conversion from K/m to K/Pa
md.constants.yts=31556926.;