[14953] | 1 | /*!\file: Exp.cpp
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| 2 | * \brief Exp.cpp: write the vertex coordinates defined in a domain
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| 3 | * outline from Argus (.exp file). The first contour in the file is for
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| 4 | * the outside domain outline.
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| 5 | */
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| 6 | #include <stdio.h>
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| 7 | #include <math.h>
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| 8 |
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| 9 | #include "../MemOps/MemOps.h"
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| 10 | #include "../Exceptions/exceptions.h"
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| 11 | #include "./exp.h"
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| 12 |
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| 13 | int ExpWrite(int nprof,int* profnvertices,double** pprofx,double** pprofy,char* domainname){/*{{{*/
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| 14 |
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| 15 | /*I/O: */
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| 16 | FILE* fid=NULL;
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| 17 |
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| 18 | /*open domain outline file for writing: */
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| 19 | if((fid=fopen(domainname,"w"))==NULL) _error_("could not open domain file " << domainname);
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| 20 |
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| 21 | /*Start writing profiles: */
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| 22 | for(int counter=0;counter<nprof;counter++){
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| 23 |
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| 24 | /*Write header: */
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| 25 | fprintf(fid,"## Name:%s\n",domainname);
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| 26 | fprintf(fid,"## Icon:0\n");
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| 27 | fprintf(fid,"# Points Count Value\n");
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| 28 | fprintf(fid,"%u %s\n",profnvertices[counter] ,"1.");
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| 29 | fprintf(fid,"# X pos Y pos\n");
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| 30 |
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| 31 | /*Write vertices: */
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| 32 | for(int i=0;i<profnvertices[counter];i++){
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| 33 | fprintf(fid,"%lf\t%lf\n",pprofx[counter][i],pprofy[counter][i]);
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| 34 | }
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| 35 |
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| 36 | /*Write blank line: */
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| 37 | if(counter<nprof-1) fprintf(fid,"\n");
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| 38 | }
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| 39 |
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| 40 | /*close Exp file: */
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| 41 | fclose(fid);
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| 42 |
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| 43 | return 1;
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| 44 | }/*}}}*/
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| 45 | int IsInPolySerial(double* in,double* xc,double* yc,int numvertices,double* x,double* y,int nods, int edgevalue){ /*{{{*/
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| 46 |
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| 47 | double x0,y0;
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| 48 |
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| 49 | /*Go through all vertices of the mesh:*/
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| 50 | for(int i=0;i<nods;i++){
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| 51 | if (in[i]){
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| 52 | /*this vertex already is inside one of the contours, continue*/
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| 53 | continue;
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| 54 | }
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| 55 | /*pick up vertex: */
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| 56 | x0=x[i];
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| 57 | y0=y[i];
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| 58 | if (pnpoly(numvertices,xc,yc,x0,y0,edgevalue)){
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| 59 | in[i]=1.;
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| 60 | }
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| 61 | else{
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| 62 | in[i]=0.;
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| 63 | }
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| 64 | }
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| 65 |
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| 66 | return 1;
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| 67 | }
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| 68 | /*}}}*/
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| 69 | /*pnpoly{{{*/
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| 70 | int pnpoly(int npol, double *xp, double *yp, double x, double y, int edgevalue) {
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| 71 | int i, j, c = 0;
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| 72 | double n1, n2, normp, scalar;
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| 73 |
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| 74 | /*first test, are they colinear? if yes, is the point in the middle of the segment*/
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| 75 | if (edgevalue != 2 ){
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| 76 | for (i = 0, j = npol-1; i < npol; j = i++) {
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| 77 | n1=pow(yp[i]-yp[j],2.0)+pow(xp[i]-xp[j],2.0);
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| 78 | n2=pow(y-yp[j],2.0)+pow(x-xp[j],2.0);
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| 79 | normp=pow(n1*n2,0.5);
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| 80 | scalar=(yp[i]-yp[j])*(y-yp[j])+(xp[i]-xp[j])*(x-xp[j]);
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| 81 |
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| 82 | if (scalar == normp){
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| 83 | if (n2<=n1){
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| 84 | c = edgevalue;
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| 85 | return c;
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| 86 | }
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| 87 | }
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| 88 | }
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| 89 | }
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| 90 | /*second test : point is neither on a vertex, nor on a side, where is it ?*/
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| 91 | for (i = 0, j = npol-1; i < npol; j = i++) {
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| 92 | if ((((yp[i]<=y) && (y<yp[j])) ||
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| 93 | ((yp[j]<=y) && (y<yp[i]))) &&
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| 94 | (x < (xp[j] - xp[i]) * (y - yp[i]) / (yp[j] - yp[i]) + xp[i])){
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| 95 | c = !c;
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| 96 | }
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| 97 | }
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| 98 | return c;
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| 99 | }/*}}}*/
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